During the latest round of the BrainBashers school triathlon the final results were mislaid, however, this is what we do know.
Hayden was fourth. Alex was not the oldest but was older than Drew, who was not second. The child who was next in age to the youngest, finished second. The child who finished in third place was older than the child who finished first. Billie was younger than the child who finished in third place.
Can you determine who finished where and place the children in order of age?
Answer # Name Age
#1 Drew youngest
#2 Billie next to youngest
#3 Alex next to oldest
#4 Hayden oldest
Reasoning
By (2), neither Alex nor Drew were the oldest. By (5), neither was Billie. Therefore, Hayden was the oldest, and by (1) came fourth.
#1
#2
#3
#4 Hayden oldest
By (4) the youngest didn't come third, and by (3) the youngest didn't come second. Therefore, the youngest came first.
#1 youngest
#2
#3
#4 Hayden oldest
By (3), the next to youngest came second, leaving the next to oldest in third.
#1 youngest
#2 next to youngest
#3 next to oldest
#4 Hayden oldest
By (2), Drew wasn't second, but Alex was older, so Drew can't be third either. Therefore, Drew can only have come in first.
#1 Drew youngest
#2 next to youngest
#3 next to oldest
#4 Hayden oldest
By (5) Billie didn't come third, so came second. Leaving Alex in third.
#1 Drew youngest
#2 Billie next to youngest
#3 Alex next to oldest
#4 Hayden oldest
??
Puzzle 46
During the recent BrainBashers cipher convention, a Morse code contest took place.
The contest consisted of a Morse code transmission where the spaces between the letters and words were missing.
Can you find the ten animals?
Luckily, BrainBashers has provided you with a list of the Morse code characters:
Hint
In order for the clocks to show the same time (e.g. 2 o'clock), what must the total time gained by one, and lost by the other, total?
Answers Midnight, 10 days later, when they will both show 4 o'clock. Midnight, 30 days later, when they will both show 12 o'clock. Reasoning #1
In order for the clocks to show the same time, the total time gained by one, and lost by the other, must be 12 hours.
For example, if the first clock were to show 2 o'clock, it would have gained 2 hours. In order for the second clock to also show 2 o'clock, it would have had to have lost 10 hours. This is a total of 12 hours gained and lost.
We know that for every hour that passes, the first clock gains one minute, and the second clock loses 2 minutes, for a total time gained and lost of 1 + 2 = 3 minutes.
The total time gained and lost will equal 12 hours when 12 x 60 ÷ 3 = 240 hours have passed. 240 hours = 10 days.
The first clock will have gained 240 x 1 minutes = 240 minutes = 4 hours.
The second clock will have lost 240 x 2 minutes = 480 minutes = 8 hours.
So, they will both show 4 o'clock, 10 days later.
Reasoning #2
In the first answer, we can see that 10 days later, the clocks both show 4 o'clock.
If we move forward another 10 days, both clocks would show 8 o'clock.
If we move forward another 10 days, both clocks would show 12 o'clock.
This will now be the correct time.
So, they will both show 12 o'clock, 30 days later.
