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Daily Sudoku Answer 



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Oct 22 - Super Hard
Puzzle Copyright © Kevin Stone

Share link – www.brainbashers.com/s278041



Reasoning 



R1C4 can only be <3>

R1C6 can only be <5>

R2C5 can only be <7>

R4C9 can only be <5>

R6C1 can only be <4>

R6C5 can only be <9>

R9C4 can only be <2>

R1C2 can only be <4>

R4C1 can only be <2>

R5C8 can only be <9>

R5C6 can only be <6>

R9C8 can only be <4>

R6C9 can only be <8>

R5C4 can only be <8>

R8C5 can only be <6>

R1C8 can only be <1>

R7C8 can only be <5>

R4C5 can only be <1>

R5C2 can only be <5>

R5C5 can only be <2>

R9C6 can only be <9>

R3C8 can only be <7>

R2C7 is the only square in row 2 that can be <4>

R7C3 is the only square in row 7 that can be <4>

R8C9 is the only square in row 8 that can be <1>

R3C7 is the only square in column 7 that can be <5>

Squares R1C3 and R1C7 in row 1 and R9C3 and R9C7 in row 9 form a Simple X-Wing pattern on possibility <6>. All other instances of this possibility in columns 3 and 7 can be removed.

R2C3 - removing <6> from <356> leaving <35>

R7C7 - removing <6> from <2689> leaving <289>

Squares R2C1 (XY), R8C1 (XZ) and R1C3 (YZ) form an XY-Wing pattern on <9>. All squares that are buddies of both the XZ and YZ squares cannot be <9>.

R8C3 - removing <9> from <259> leaving <25>

R3C1 - removing <9> from <89> leaving <8>

Squares R7C1 and R7C9 in row 7 form a simple naked pair. These 2 squares both contain the 2 possibilities <69>. Since each of the squares must contain one of the possibilities, they can be eliminated from the other squares in the row.

R7C7 - removing <9> from <289> leaving <28>

The puzzle can be reduced to a Bivalue Universal Grave (BUG) pattern, by making this reduction:

R3C3=<29>

These are called the BUG possibilities. In a BUG pattern, in each row, column and block, each unsolved possibility appears exactly twice. Such a pattern either has 0 or 2 solutions, so it cannot be part of a valid Sudoku

When a puzzle contains a BUG, and only one square in the puzzle has more than 2 possibilities, the only way to kill the BUG is to remove both of the BUG possibilities from the square, thus solving it

R3C3 - removing <29> from <239> leaving <3>

R3C2 can only be <2>

R3C9 can only be <9>

R2C3 can only be <5>

R9C3 can only be <6>

R7C9 can only be <6>

R1C7 can only be <6>

R7C1 can only be <9>

R2C9 can only be <3>

R9C7 can only be <8>

R1C3 can only be <9>

R9C2 can only be <3>

R7C7 can only be <2>

R2C1 can only be <6>

R8C3 can only be <2>

R7C2 can only be <8>

R8C1 can only be <5>

R8C7 can only be <9>



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