Daily Sudoku Answer 

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R5C5 can only be <9>

R9C6 can only be <5>

R7C6 can only be <3>

R1C7 is the only square in row 1 that can be <8>

R2C3 is the only square in row 2 that can be <5>

R3C5 is the only square in row 3 that can be <5>

R4C1 is the only square in row 4 that can be <8>

R7C9 is the only square in row 7 that can be <5>

R4C7 is the only square in row 4 that can be <5>

R7C4 is the only square in row 7 that can be <8>

R8C3 is the only square in row 8 that can be <1>

R6C1 is the only square in row 6 that can be <1>

R7C5 is the only square in row 7 that can be <1>

R9C5 can only be <2>

R9C4 can only be <9>

R1C5 can only be <3>

R8C2 is the only square in row 8 that can be <3>

R2C7 is the only square in row 2 that can be <3>

R3C1 is the only square in row 3 that can be <3>

R3C6 is the only square in row 3 that can be <6>

R1C6 can only be <4>

R9C9 is the only square in row 9 that can be <1>

R1C1 is the only square in column 1 that can be <9>

R1C3 is the only square in row 1 that can be <6>

R9C1 is the only square in row 9 that can be <6>

R7C2 is the only square in column 2 that can be <2>

Squares R2C8 and R7C8 in column 8 form a simple naked pair. These 2 squares both contain the 2 possibilities <47>. Since each of the squares must contain one of the possibilities, they can be eliminated from the other squares in the column.

R3C8 - removing <47> from <2479> leaving <29>

Squares R1C9 and R4C9 in column 9 form a simple naked pair. These 2 squares both contain the 2 possibilities <27>. Since each of the squares must contain one of the possibilities, they can be eliminated from the other squares in the column.

R3C9 - removing <27> from <2479> leaving <49>

R5C9 - removing <27> from <2347> leaving <34>

Squares R5C9<34>, R6C7<49> and R6C9<349> in block 6 form a comprehensive naked triplet. These 3 squares can only contain the 3 possibilities <349>. Since each of the squares must contain one of the possibilities, they can be eliminated from the other squares in the block.

R5C7 - removing <4> from <247> leaving <27>

Squares R5C1 and R9C7 form a remote naked pair. <47> can be removed from any square that is common to their groups.

R5C7 - removing <7> from <27> leaving <2>

R8C7 can only be <9>

R4C9 can only be <7>

R8C8 can only be <2>

R6C7 can only be <4>

R3C8 can only be <9>

R3C9 can only be <4>

R3C2 can only be <7>

R5C9 can only be <3>

R2C8 can only be <7>

R4C3 can only be <2>

R1C9 can only be <2>

R6C9 can only be <9>

R6C3 can only be <3>

R9C7 can only be <7>

R9C3 can only be <4>

R7C8 can only be <4>

R1C4 can only be <7>

R2C2 can only be <4>

R3C4 can only be <2>

R7C1 can only be <7>

R5C3 can only be <7>

R5C1 can only be <4>

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