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Daily Sudoku Answer 



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May 14 - Super Hard
Puzzle Copyright © Kevin Stone

Share link – www.brainbashers.com/s333549



Reasoning 



R1C9 can only be <8>

R3C2 can only be <9>

R5C5 can only be <5>

R8C7 can only be <5>

R2C7 can only be <9>

R3C8 can only be <2>

R1C1 can only be <5>

R3C6 can only be <7>

R4C7 can only be <8>

R2C3 can only be <8>

R2C4 can only be <5>

R3C4 can only be <8>

R6C7 can only be <1>

R6C2 can only be <2>

R4C9 is the only square in row 4 that can be <2>

R5C2 is the only square in row 5 that can be <1>

R6C9 is the only square in row 6 that can be <6>

R6C1 is the only square in row 6 that can be <8>

R7C6 is the only square in row 7 that can be <5>

R9C4 is the only square in row 9 that can be <6>

Squares R8C3 and R8C4 in row 8 form a simple naked pair. These 2 squares both contain the 2 possibilities <37>. Since each of the squares must contain one of the possibilities, they can be eliminated from the other squares in the row.

R8C5 - removing <3> from <239> leaving <29>

Intersection of row 5 with block 6. The value <3> only appears in one or more of squares R5C7, R5C8 and R5C9 of row 5. These squares are the ones that intersect with block 6. Thus, the other (non-intersecting) squares of block 6 cannot contain this value.

R4C8 - removing <3> from <359> leaving <59>

Squares R5C1 and R9C1 in column 1 and R5C9 and R9C9 in column 9 form a Simple X-Wing pattern on possibility <7>. All other instances of this possibility in rows 5 and 9 can be removed.

R5C8 - removing <7> from <379> leaving <39>

The puzzle can be reduced to a Bivalue Universal Grave (BUG) pattern, by making this reduction:

R7C4=<47>

These are called the BUG possibilities. In a BUG pattern, in each row, column and block, each unsolved possibility appears exactly twice. Such a pattern either has 0 or 2 solutions, so it cannot be part of a valid Sudoku

When a puzzle contains a BUG, and only one square in the puzzle has more than 2 possibilities, the only way to kill the BUG is to remove both of the BUG possibilities from the square, thus solving it

R7C4 - removing <47> from <347> leaving <3>

R7C2 can only be <4>

R7C8 can only be <7>

R1C4 can only be <4>

R8C4 can only be <7>

R9C5 can only be <1>

R6C8 can only be <5>

R9C9 can only be <3>

R8C3 can only be <3>

R9C6 can only be <4>

R2C5 can only be <2>

R9C1 can only be <7>

R1C6 can only be <9>

R5C9 can only be <7>

R1C5 can only be <3>

R8C6 can only be <2>

R2C6 can only be <1>

R8C5 can only be <9>

R5C1 can only be <9>

R6C3 can only be <7>

R4C8 can only be <9>

R4C2 can only be <3>

R4C3 can only be <5>

R4C1 can only be <4>

R5C8 can only be <3>



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