## Puzzle 9

**Bank Robbery #1** - Logic Puzzles

After a local bank robbery, five suspects were interviewed.

Below is a summary of their statements.

Police know that each of them told the truth in one of the statements and lied in the other.

From this information, can you work out who committed the crime?

Billie said:

It wasn't Chris

It was Alex

Drew said:

It was Chris

It wasn't Alex

Chris said:

It was Billie

It wasn't Emery

Alex said:

It was Emery

It wasn't Billie

Emery said:

It was Drew

It was Alex

Puzzle Copyright © Kevin Stone

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Hint

Take a close look at Emery's statements.

Answer

Drew.

Reasoning

Since each suspect told the truth just once, Emery's statements mean that it was either Drew or Alex.

If it was Alex, then both of Billie's statements would be true, which isn't allowed (and similarly both of Drew's would be false).

Therefore, it was Drew.

This can be double-checked with all of the other statements.

## Puzzle 10

Can you draw a continuous line that goes through every number in order, starting with 1, and ending with 6?

You can only move horizontally and vertically, every square must be visited, and the line must not cross itself.

**Note:** this puzzle isn't interactive, and the squares can't be clicked.

Puzzle Copyright © Cihan Altay

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Hint

From the 1 go straight down.

Answer

## Puzzle 11

At the local sweet shop, three particularly nice sweets are on special offer.

A Nobbler is over three times the price of a Sparkle.

Six Sparkles are worth more than a Wibbler.

A Nobbler, plus two Sparkles costs less than a Wibbler.

A Sparkle, a Wibbler and a Nobbler together cost 40p.

Can you determine the price of each type of sweet?

Puzzle Copyright © Kevin Stone

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Hint

Which sweet is the least expensive?

Answer

Sparkle = 4p

Wibbler = 23p

Nobbler = 13p

Reasoning

By (3) a Nobbler, plus two Sparkles costs less than a Wibbler, therefore a Wibbler must be the most expensive sweet.

By (1) a Nobbler is over three times the price of a Sparkle, therefore a Sparkle must be the cheapest sweet.

So the order of sweets, from the least to most expensive, is **Sparkle, Nobbler, Wibbler**.

If a Sparkle was 1p, by (2) a Wibbler could only be up to 5p, by (4) a Nobbler would cost at least 34p, which is more than a Wibbler and isn't allowed as the Wibbler is the most expensive sweet.

If a Sparkle was 2p, by (2) a Wibbler could only be up to 11p, by (4) a Nobbler would cost at least 27p, which is more than a Wibbler and isn't allowed as the Wibbler is the most expensive sweet.

If a Sparkle was 3p, by (2) a Wibbler could only be up to 17p, by (4) a Nobbler would cost at least 20p, which is more than a Wibbler and isn't allowed as the Wibbler is the most expensive sweet.

So a Sparkle must be at least 4p.

If a Sparkle was 4p, by (1) a Nobbler must be at least 13p, by (4) a Wibbler would cost 23p – **this combination matches all of the clues** and is a possible solution.

If a Sparkle was 4p and a Nobbler 14p, by (4) a Wibbler would cost 22p. This would not satisfy (3). And if we increase the price of a Nobbler, (3) is never satisfied.

If a Sparkle was 5p, by (1) a Nobbler must be at least 16p, by (4) making a Wibbler at most 19p. This would not satisfy (3).

If we increase the price of a Sparkle or Nobbler further, (3) is will never be satisfied.

Therefore, the only solution we came across must be the correct one.

## Puzzle 12

Below are thirteen 5-letter words, each of which has had two of its letters removed.

In total, these 26 letters are A to Z.

The remaining letters in each word are in the correct order.

There are no words that are spelled differently based on location (favour / favor, etc) and there are no plurals.

Can you find the original words?

-e-rd
-u-et
wa-t-
-um-y
-e-er
a-o-e
mi--d
-hew-
hu-i-
-abi-
co--h
ho--e
arg--

Puzzle Copyright © Kevin Stone

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Hint

The first word is BEARD.

Answers

-e-rd = beard (BA)
-u-et = quiet (QI)
wa-t- = waltz (LZ)
-um-y = jumpy (JP)
-e-er = fever (FV)
a-o-e = awoke (WK)
mi--d = mixed (XE)
-hew- = chewy (CY)
hu-i- = humid (MD)
-abi- = habit (HT)
co--h = cough (UG)
ho--e = horse (RS)
arg-- = argon (ON)

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