The second letters of each word are the vowels in alphabetical order, fAwn, bEar, lIon, mOle, dUck.
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Puzzle 2
Can you find five countries hidden in the following paragraph:
Dominic had a certain way with animals, he could almost talk to them. By tickling it under the chin, a rabbit would roll over and let its belly be tickled. This technique was sometimes used to good effect in gaining trust, and allowed a vital yearly treatment to be performed safely. The removal of nits. Using a vet approved shampoo to clean the fur (and not a blend of malt and water!).
Hint
One of the countries begins with the letter M.
Answers
Chad, China, Togo, Italy, Malta.
Domini[c had] a certain way with animals, he could almost talk to them. By tickling it under the [chin, a] rabbit would roll over and let its belly be tickled. This technique was sometimes used [to go]od effect in gaining trust, and allowed a v[ital y]early treatment to be performed safely. The removal of nits. Using a vet approved shampoo to clean the fur (and not a blend of [malt a]nd water!).
Hint
A very tricky puzzle involving prime numbers.
Answer
101.
These are prime numbers, which, when reversed, are also prime.
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Puzzle 4
At the local sweet shop, three particularly nice sweets are on special offer.
A Nobbler is over three times the price of a Sparkle. Six Sparkles are worth more than a Wibbler. A Nobbler, plus two Sparkles costs less than a Wibbler. A Sparkle, a Wibbler and a Nobbler together cost 40p.
Can you determine the price of each type of sweet?
Reasoning
By (3) a Nobbler, plus two Sparkles costs less than a Wibbler, therefore a Wibbler must be the most expensive sweet.
By (1) a Nobbler is over three times the price of a Sparkle, therefore a Sparkle must be the cheapest sweet.
So the order of sweets, from the least to most expensive, is Sparkle, Nobbler, Wibbler.
If a Sparkle was 1p, by (2) a Wibbler could only be up to 5p, by (4) a Nobbler would cost at least 34p, which is more than a Wibbler and isn't allowed as the Wibbler is the most expensive sweet.
If a Sparkle was 2p, by (2) a Wibbler could only be up to 11p, by (4) a Nobbler would cost at least 27p, which is more than a Wibbler and isn't allowed as the Wibbler is the most expensive sweet.
If a Sparkle was 3p, by (2) a Wibbler could only be up to 17p, by (4) a Nobbler would cost at least 20p, which is more than a Wibbler and isn't allowed as the Wibbler is the most expensive sweet.
So a Sparkle must be at least 4p.
If a Sparkle was 4p, by (1) a Nobbler must be at least 13p, by (4) a Wibbler would cost 23p. This combination matches all of the clues and is a possible solution.
If a Sparkle was 4p and a Nobbler 14p, by (4) a Wibbler would cost 22p. This would not satisfy (3). And if we increase the price of a Nobbler, (3) is never satisfied.
If a Sparkle was 5p, by (1) a Nobbler must be at least 16p, by (4) making a Wibbler at most 19p. This would not satisfy (3).
If we increase the price of a Sparkle or Nobbler further, (3) is will never be satisfied.
Therefore, the only solution we came across must be the correct one.
