Puzzle 1
Which number, when written as a word, makes this true:
Cleverly, there are exactly ? E's in this sentence.
Puzzle Copyright © Kevin Stone
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Hint
Does ONE work, does TWO work? How many E's are there already?
Answer
Twelve.
"Cleverly, there are exactly twelve E's in this sentence."
Puzzle 2
This BrainBashers safe has a rather unusual control panel.
In order to open the safe, you have to press every single square once only, in the correct sequence, ending on the square marked E .
Each square indicates which square to press next, for example, 2U means move up 2 squares and 3R means move right 3 squares.
Can you determine which square you must start with?
6D
6D
1R
1R
1R
1R
1D
2D
1D
1U
2L
1R
2D
2L
2U
4R
1U
3R
2D
5L
2L
1R
3U
1U
2D
E
2D
3L
3U
1L
1U
2L
2D
2L
1L
1R
3R
1U
3U
2U
1D
2U
1U
2R
1U
5U
2L
1R
2U
Note: this puzzle is not interactive, and the safe buttons cannot be clicked.
Puzzle Copyright © Kevin Stone
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Hint
Start on any square, and see how far you can get.
Answer
Start from the 2U, which is on the 6th row down and the 7th column across.
Puzzle 3
Which is larger:
centimetres in a mile
miles travelled by light in a second
Puzzle Copyright © Kevin Stone
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Hint
Light travels over 186,000 miles each second.
Answer
Miles travelled by light in a second.
Reasoning
Light travels over 186,000 miles per second.
There are 2.54cm in an inch, 12 inches in a foot, 3 feet in a yard, and 1760 yards in a mile. So there are 2.54 x 12 x 3 x 1760 = 160,934.4cm in a mile.
Puzzle 4
What 5-digit number am I thinking of?
It has two prime digits.
Digit 3 is the highest digit.
Digit 2 is the lowest digit.
Digit 1 is higher than the sum of digits 4 and 5.
Digit 5 is half of digit 4.
Digit 1 is one smaller than digit 3.
Digit 5 is between digit 2 and digit 1
The digit 0 doesn't appear, and there are no duplicates. Don't forget that 1 isn't prime, as the prime numbers start with 2, 3, 5, …
Puzzle Copyright © Kevin Stone
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Hint
What can digits 4 and 5 be?
Answer
71842.
Reasoning
The number can be represented as:
- - - - -
By (5), Digit 5 is half of Digit 4, so we have four possibilities:
- - - 2 1
- - - 4 2
- - - 6 3
- - - 8 4
By (4), Digit 1 is higher than the sum of Digit 4 and Digit 5, so we can eliminate two possibilities, leaving:
- - - 2 1
- - - 4 2
By (7), Digit 5 is between Digit 2 and Digit 1, so we can eliminate - - - 2 1, leaving:
- - - 4 2
By (4), Digit 1 must be higher than the sum of Digit 4 and Digit 5, so we have three possibilities:
7 - - 4 2
8 - - 4 2
9 - - 4 2
By (6), Digit 1 is 1 smaller than Digit 3 we can eliminate 9 - - 4 2, and fill in Digit 3, leaving:
7 - 8 4 2
8 - 9 4 2
By (3), Digit 2 is the lowest digit, and must be 1:
7 1 8 4 2
8 1 9 4 2
By (1), the only possibility is:
7 1 8 4 2
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