The results of a recent Chess tournament between five close rivals is described below:
Dale finished before Alex. Emery finished after Bailey. Alex finished before Chris. Emery finished after Dale. Bailey finished before Alex. Dale finished after Bailey. Chris finished before Emery.
Who finished where?
Hint
Try rewriting each statement so that they are all 'finished before' statements instead.
Answer
Bailey won …
… then Dale, Alex, Chris, and Emery.
Reasoning
By placing the person who finished higher to the left, we have:
Dale finished before Alex (Dale > Alex)Emery finished after Bailey (Bailey > Emery)Alex finished before Chris (Alex > Chris)Emery finished after Dale (Dale > Emery)Bailey finished before Alex (Bailey > Alex)Dale finished after Bailey (Bailey > Dale)Chris finished before Emery (Chris > Emery)
From (1) and (3):
Dale > Alex > Chris
Adding (7):
Dale > Alex > Chris > Emery
Adding (6):
Bailey > Dale > Alex > Chris > Emery
Which is the final placing for all the players, and can be double-checked with the remaining clues.
Digit 2 is smaller than Digit 4Digit 4 is two thirds of Digit 1Digit 1 is two thirds of Digit 3Digit 3 is three times Digit 2
By (3), Digit 3 is divisible by 3:
Digit 3 = 3, 6, 9
By (3), Digit 1 is two thirds of Digit 3:
Digit 1 = 2, 4, 6.
But, by (2), Digit 1 is divisible by 3:
Digit 1 = 6, and Digit 3 = 9.
By (4), Digit 3 is three times Digit 2:
Digit 2 = 3.
By (2), Digit 4 is two thirds of Digit 1:
Digit 4 = 4.
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