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Puzzle 165
In this puzzle, all of the numbers from 1 to 8 are used.
The differences (larger – smaller) between any two connected numbers are all different.
Can you complete the grid?
Note: this puzzle is not interactive, and cannot be clicked.
Reasoning
The first observation is that all of the possible gaps must exist: 1, 2, 3, 4, 5, 6, 7, and let's call these Gap1, …, Gap7.
Looking at Gap7, this can only happen when:
[Gap7a: 1 is next to 8]
Looking at Gap6, this can happen when:
[Gap6a: 1 is next to 7]
this is not allowed because 1 and 7 are given squares that are not next to each other.
[Gap6b: 2 is next to 8]
Looking at Gap5, this can happen when:
[Gap5a: 1 is next to 6]
[Gap5b: 2 is next to 7]
this is not allowed because [Gap6b: 2 is next to 8], which would mean that we can't also have [Gap7a: 1 is next to 8].
[Gap5c: 3 is next to 8]
this is not allowed because we couldn't then also have: [Gap7a: 1 is next to 8] and [Gap6b: 2 is next to 8].
We can't have the 8 above the 1, as there is then no place for [Gap6b: 2 is next to 8].
So, we have two possible places for the 8, to the left of the 1, or to the right of the 1.
8 to the left of 1
What can we place to the right of 1?
3 – no, because the gap between the 1 and 3, and the gap between 3 and 5, are both 2.
4 – no, because the gap between 4 and 5 is 1, which we already have.
6 – no, because the gap between 5 and 6 is 1, which we already have.
So the 8 can't go to the left of 1.
8 to the right of 1
We know [Gap5a: 1 is next to 6].
Let's try 6 to the left of 1. No matter where we place the 3 and 4 we end up with duplicate gaps. So this doesn't work.
So, the 6 must go above 1, but the 4 can't go to the left of 1 because of duplicate gaps. Therefore, this doesn't work either.
Which means that the final answer is:
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Puzzle 166
By changing the third letter of each of the words below, can you make another valid word?
You have to change each word such that the third letters will reveal a ten-letter word when read downwards.
Therefore, what now reads 'krzsaprokd' will be a real word. bakecuremazepestneatropeportfoodpokesoda
Answers There are 147 pages.The number 3 appears 35 times. Answer #1
For pages 1-9, there are 9 pages, which is 9 digits.
For pages 10-99, there are 90 pages, which is 180 digits.
This is a total so far of 189, therefore we require another 333 – 189 = 144 digits, which is another 144 ÷ 3 = 48 pages.
Taking us to 9 + 90 + 48 = 147 pages in total.
Answer #2
From page 1 to 147 we have 15 pages that end in 3:
3, 13, 23, …, 143
We also have the ten pages that start with 30:
30, 31, 32, …, 39
Plus the ten pages that start with 130:
130, 131, 132, …, 139
For a total of 15 + 10 + 10 = 35 number 3's.
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It is now three years since I first asked for support, and I would like to sincerely thank everyone who has helped me. BrainBashers doesn't show adverts, and I continue to depend on the ongoing support from everyone who enjoys the site.
