Puzzle 285
Below you will find 15 well-known five-letter words, with only their endings remaining.
Can you find the words?
--lta
--yss
--pty
--dth
--day
--ybe
--dex
--fth
--nda
--aph
--alp
--era
--njo
--eue
--xty
Puzzle Copyright © Kevin Stone
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Hint
The first 5 words begin with D, A, E, W, T.
Answers
--lta = delta
--yss = abyss
--pty = empty
--dth = width
--day = today
--ybe = maybe
--dex = index or codex
--fth = fifth
--nda = panda
--aph = graph
--alp = scalp
--era = opera
--njo = banjo
--eue = queue
--xty = sixty
Puzzle 286
What letter comes next in this sequence:
E · O · E · R · E · ?
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Hint
This is a very common sequence.
Answer
X.
The last letters of the words one, two, three, four, five, six .
Puzzle 287
What is the next number in this sequence:
100 · 365 · 24 · 60 · ?
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Hint
The answers are related to time.
Answer
60.
The numbers represent 100 years in a century, 365 days in a year, 24 hours in a day, 60 minutes in an hour and 60 seconds in an minute.
Puzzle 288
What 5-digit number am I thinking of?
It has two prime digits.
Digit 3 is the highest digit.
Digit 2 is the lowest digit.
Digit 1 is higher than the sum of digits 4 and 5.
Digit 5 is half of digit 4.
Digit 1 is one smaller than digit 3.
Digit 5 is between digit 2 and digit 1
The digit 0 doesn't appear, and there are no duplicates. Don't forget that 1 isn't prime, as the prime numbers start with 2, 3, 5, …
Puzzle Copyright © Kevin Stone
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Hint
What can digits 4 and 5 be?
Answer
71842.
Reasoning
The number can be represented as:
- - - - -
By (5), Digit 5 is half of Digit 4, so we have four possibilities:
- - - 2 1
- - - 4 2
- - - 6 3
- - - 8 4
By (4), Digit 1 is higher than the sum of Digit 4 and Digit 5, so we can eliminate two possibilities, leaving:
- - - 2 1
- - - 4 2
By (7), Digit 5 is between Digit 2 and Digit 1, so we can eliminate - - - 2 1, leaving:
- - - 4 2
By (4), Digit 1 must be higher than the sum of Digit 4 and Digit 5, so we have three possibilities:
7 - - 4 2
8 - - 4 2
9 - - 4 2
By (6), Digit 1 is 1 smaller than Digit 3 we can eliminate 9 - - 4 2, and fill in Digit 3, leaving:
7 - 8 4 2
8 - 9 4 2
By (3), Digit 2 is the lowest digit, and must be 1:
7 1 8 4 2
8 1 9 4 2
By (1), the only possibility is:
7 1 8 4 2
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