Puzzle 121
Can you find every occurrence of the word JANUARY that appears in this grid (horizontally, vertically, or diagonally)?
The hint will reveal the number of times it occurs, but where are they?
Note: this puzzle is not interactive, and the letters cannot be selected.
Puzzle Copyright © Kevin Stone
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Hint
The word JANUARY appears 10 times.
Answer
The word JANUARY appears 10 times.
Puzzle 122
Horses is to equine...
...as cattle is to bovine...
...as sheep is to ovine...
...as deer is to {?}.
Puzzle Copyright © Kevin Stone
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Hint
You might need a dictionary.
Answer
Cervine.
The adjective for deer-like.
Puzzle 123
Which is larger?
3 raised to the 5th power
5 raised to the 3rd power
Puzzle Copyright © Kevin Stone
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Hint
3 raised to the 5th power is 3 x 3 x 3 x 3 x 3.
Answer
3 raised to 5th power.
Reasoning
3 raised to the 5th power = 3 ^ 5 = 3 x 3 x 3 x 3 x 3 = 243
and
5 raised to the 3rd power = 5 ^ 3 = 5 x 5 x 5 = 125.
Puzzle 124
Four shepherds were watching over their flocks, and they were commenting on how many sheep they each had.
If Alex had three more sheep, then he'd have one fewer sheep than Billie.
Whereas Drew has the same number as the other three shepherds put together.
If Charlie had three fewer sheep, he'd have exactly three times the number of Alex.
If they were evenly distributed, they'd each have eleven sheep.
How many sheep does Alex have?
Puzzle Copyright © Kevin Stone
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Hint
Find how many sheep Drew has first.
Answer
3.
Reasoning
If we denote Alex by A, Billie by B, Charlie by C, and Drew by D and number the clues.
If Alex had three more sheep, then he'd have one fewer sheep than Billie.
Whereas Drew has the same number as the other three shepherds put together.
If Charlie had three fewer sheep, he'd have exactly three times the number of Alex.
If they were evenly distributed, they'd each have eleven sheep.
By (4):
A + B + C + D = 44
And, by (2), these are shared equally between A + B + C and D.
So D = 22, and A + B + C = 22 (*)
By (1):
A + 3 = B – 1
A + 4 = B
By (3):
C – 3 = 3A
C = 3A + 3
Substitute B and C in (*):
A + (A+4) + (3A+3) = 22
5A + 7 = 22
5A = 15
A = 3
And, B = 7, C = 12.
Double-Checking
A = 3, B = 7, C = 12, D = 22.
(1) 3 + 3 = 7 – 1
(2) 3 + 7 + 12 = 22
(3) 12 – 3 = 3 x 3
(4) 3 + 7 + 12 + 22 = 44, and 44 ÷ 4 = 11 each.
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