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Workings

Hint
The fourth player is the key to this tricky question.

Answer
9 points.

Respectively the scores were 7, 14, 20, 30, 23, 9.

Reasoning
If we label the six players A, B, C, D, E, and F, we know that:

[1]  A + B + C + D + E + F = 103

and from the clues:

   A = B ÷ 2
   B = C − 6
   C = D x 2 ÷ 3
   E = D − A
   F = E − 14

Note that it could be E = A − D or E = D − A, but using A − D we'd end up with a negative value for E later, which isn't allowed (so we'd have to try again with D − A anyway).

As we have no information for D, it's best to find all of the other letters in terms of D. These steps are left as an exercise (e.g. use C in the equation for B), but the result is:

   A = ( D −  9) ÷ 3
   B = (2D − 18) ÷ 3
   C = (2D     ) ÷ 3
   D = (3D     ) ÷ 3
   E = (2D +  9) ÷ 3
   F = (2D − 33) ÷ 3

Writing it as D = 3D ÷ 3 makes things slightly clearer in the next step.

We then use these in [1] to find that:

   (12D − 51) ÷ 3 = 103
         12D − 51 = 309
              12D = 360
                D = 30

Therefore, F = (2D − 33) ÷ 3 = 9.

Workings

Hint
Oval becomes Opal.

Answers
Paperweight.
opal past spin melt wren swab mess find aged shed stay

Workings

Hint
Try rewriting each statement so that they are all 'finished before' statements instead.

Answer
Bailey won …

… then Dale, Alex, Chris, and Emery.

Reasoning
By placing the person who finished higher to the left, we have:

Dale finished before Alex (Dale > Alex) Emery finished after Bailey (Bailey > Emery) Alex finished before Chris (Alex > Chris) Emery finished after Dale (Dale > Emery) Bailey finished before Alex (Bailey > Alex) Dale finished after Bailey (Bailey > Dale) Chris finished before Emery (Chris > Emery)
From (1) and (3):

   Dale > Alex > Chris

Adding (7):

   Dale > Alex > Chris > Emery

Adding (6):

   Bailey > Dale > Alex > Chris > Emery

Which is the final placing for all the players, and can be double-checked with the remaining clues.

Workings

Hint
How old could Glen be?

Answer
Name    Age    Chess  Croquet
Dale    15     3      1
Emery   16     1      4
Frankie 18     2      2
Glen    19     4      3

Reasoning
The possible ages are: 15, 16, 18, 19.

Breaking the clues down, and numbering them:
Frankie beat Glen in chess. Dale came third (chess). The 16-year-old won (chess). Frankie came second in croquet. The 15-year-old won (croquet). Dale beat the 18-year-old (croquet). The 19-year-old came third (croquet). Emery is 3 years younger than Glen. The person who came last in chess came third in croquet. Only one person got the same position in both games.
By (4), Frankie came 2^nd in croquet.
Name    Age    Chess  Croquet
Dale
Emery
Frankie               2
Glen

By (2), Dale came 3^rd in chess.
Name    Age    Chess  Croquet
Dale           3
Emery
Frankie               2
Glen

By (8), Emery is 15 or 16, and Glen is 18 or 19.

By (9), the person who came 4^th in chess, came 3^rd in croquet, and by (7), they are 19. This can't be Dale (3^rd in chess), or Frankie (2^nd in croquet), or Emery (aged 15 or 16), so it must be Glen.
Name    Age    Chess  Croquet
Dale           3
Emery
Frankie               2
Glen    19     4      3

By (6), Dale can't have been 4^th in croquet, so must be 1^st. Leaving Emery in 4^th.
Name    Age    Chess  Croquet
Dale           3      1
Emery                 4
Frankie               2
Glen    19     4      3

By (10), only one person got the same position in both games, this can't be Emery 4^th in both (as Glen is already 4^th in chess), so must be Frank, 2^nd in both. Leaving Emery 1^st in chess.
Name    Age    Chess  Croquet
Dale           3      1
Emery          1      4
Frankie        2      2
Glen    19     4      3

By (3) and (5) we know the ages of the winners in each competition, and Frankie is therefore 18.
Name    Age    Chess  Croquet
Dale    15     3      1
Emery   16     1      4
Frankie 18     2      2
Glen    19     4      3