After the recent BrainBashers annual marathon, the judges were comparing notes to determine who finished where. From their notes, can you help them reconstruct the final result?
Max Merrymood beat Toby Trent and Jesse Jackson. Pat Piper beat Jesse Jackson, Toby Trent, and Alex Ardle. Zeb Zebra lost to Pat Piper. Glenn Goodfellow beat Toby Trent Zeb Zebra beat Frankie Flint. Glenn Goodfellow lost to Frankie Flint and Pat Piper. Toby Trent beat Billie Brick. Alex Ardle beat Zeb Zebra, Kelly Kingfisher, and Glenn Goodfellow. Kelly Kingfisher lost to Glenn Goodfellow and Max Merrymood. Billie Brick beat Kelly Kingfisher. Max Merrymood lost to Alex Ardle and Zeb Zebra. Frankie Flint beat Toby Trent, Max Merrymood, and Billie Brick. Toby Trent lost to Jesse Jackson and Alex Ardle. Jesse Jackson beat Glenn Goodfellow and Billie Brick.
Hint
Try rewriting the clues so that those who finished ahead are written first.
Answer
Pat Piper (P)
Alex Ardle (A)
Zeb Zebra (Z)
Frankie Flint (F)
Max Merrymood (M)
Jesse Jackson (J)
Glenn Goodfellow (G)
Toby Trent (T)
Billie Brick (B)
Kelly Kingfisher (K)
Reasoning
If we number the clues, write each name using a single letter, and rewrite the clues so that those who finished ahead are written first:
M beat T and JP beat J, T, and AP beat ZG beat TZ beat FF and P beat GT beat BA beat Z, K, and GG and M beat KB beat KA and Z beat MF beat T, M, and BJ and A beat TJ beat G and B
By (2): P A
By (8): P A Z
By (5): P A Z F
By (12): P A Z F M
By (1): P A Z F M J
By (14): P A Z F M J G
By (4): P A Z F M J G T
By (7): P A Z F M J G T B
By (10): P A Z F M J G T B K
??
Puzzle 2
For being well-behaved at the garden fayre, four children were each given two sweets.
Jesse had an orange sweet. One child who had a red sweet also had a blue one. No child had two sweets of the same colour. A child who had a green sweet also had a red one. Jamie didn't have a red sweet, and Jo had a green one. Jordan didn't have an orange one, and Jesse had no blue sweets.
Knowing that there were two sweets of each colour, can you tell the colours of the sweets each child had?
Answer
Jamie Orange Blue
Jesse Orange Green
Jo Green Red
Jordan Red Blue
Reasoning
The children were: Jamie, Jesse, Jo, Jordan.
The colours were: Blue, Green, Orange, Red.
There were two sweets of each colour, and by (3) no child had two sweets of the same colour.
By (1), Jesse had an Orange sweet …
… by (6), didn't have Blue …
… by (2) and (4), Red was paired with Blue and Green …
… therefore, Jesse's other sweet can't have been Red, so was Green.
Jamie
Jesse Orange Green
Jo
Jordan
By (4) the other Green sweet was paired with Red, by (5) this must have been Jo.
Jamie
Jesse Orange Green
Jo Green Red
Jordan
By (2) the other Red sweet was paired with Blue, but by (5) this wasn't Jamie, so must have been Jordan.
Jamie
Jesse Orange Green
Jo Green Red
Jordan Red Blue
Leaving Jamie with Orange and Blue.
Jamie Orange Blue
Jesse Orange Green
Jo Green Red
Jordan Red Blue
?
Puzzle 3
Which is larger:
seconds in a year.miles that light can travel in 3 minutes.
