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In the illustration we have a sketch of Sir Edwyn de Tudor going to rescue his love, who was held a captive by a neighbouring wicked baron.
Sir Edwyn calculated that if he rode at fifteen miles an hour he would arrive at the castle an hour too soon, while if he rode at ten miles an hour he would get there just an hour too late.
Now, it was of the first importance that he should arrive at the exact time appointed, in order that the rescue that he had planned should be a success, and the time of the tryst was five o'clock, when the captive would be taking afternoon tea.
The puzzle is to discover exactly how far Sir Edwyn de Tudor had to ride.
[Puzzle Code = ZBVT] Sir Edwyn De Tudor. From Amusements In Mathematics by Henry Ernest Dudeney (1917).
Direct Link: www.brainbashers.com?ZBVT
Hint: The gap between the two options is 2 hours.
Answer: The distance must have been sixty miles.
If Sir Edwyn left at noon and rode 15 miles an hour, he would arrive at four o'clock  an hour too soon. If he rode 10 miles an hour, he would arrive at six o'clock  an hour too late. But if he went at 12 miles an hour, he would reach the castle of the wicked baron exactly at five o'clock  the time appointed.
The text above is the answer given in the book, and below is a method of finding the answer.
If we call the distance to the castle, D and using the fact that Time = Distance ÷ Speed, we have:
Travelling at 15 mph:
Time1 = D ÷ 15 (an hour too soon)
Travelling at 10 mph:
Time2 = D ÷ 10 (an hour too late)
The time gap between these two times is 2 hours, therefore
Time2  Time1 = 2
D ÷ 10  D ÷ 15 = 2
Multiply throughout by 30:
3D  2D = 60
D = 60 miles.
Puzzle 4
A kind old person decided to give 12 sweets to each of the adults in the town and 8 sweets to each of the children.
Of the 612 people in the town, only half the adults and three quarters of the children took the sweets.
How many sweets did the kind old person have to buy?
Hint: The number of adults and children doesn't matter.
Answer: 3,672.
The actual number of adults and children doesn't actually matter!
If all of the people were adults then half of them (306) would be given 12 sweets:
306 x 12 = 3672
If all of the people were children then three quarters of them (459) would be given 8 sweets:
459 x 8 = 3672
If there were 512 adults (so 256 would get 12 sweets = 3072) and 100 children (so 75 would get 8 sweets = 600):
256 x 12 + 75 x 8 = 3672
We can change the numbers of adults and children, but it doesn't change the answer. The reason for this lies in the fact that 1/2 adults x 12 sweets = 3/4 children x 8 sweets (both are 6).
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