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If we denote Alan by A, Brian by B, Charles by C and Dave by D we can find the answer in the following way. Since A + B + C = D and A + B + C + D = 44, it is easy to see that D has 22 sheep. So A + B + C = 22. We can use this along with the two other facts, A + 3 = B - 1 and C - 3 = 3A, to find that A has 3, B has 7, C has 12 and D has 22. In a little more detail:

A + B + C = 22 (1)
A + 3 = B - 1 (2)
C - 3 = 3A (3)

Rearrange (3) to give C = 3A + 3 and replace the C in (1) to give A + B + 3A + 3 = 22. Simplified this gives B = 19 - 4A (4). Rearrange (2) to give B - A = 4. Use (4) in the place of B to give 19 - 4A - A = 4 to give A = 3. Now use A to work out B, and then C. QED.

Puzzle 50

How can you get ten horses into nine stables, one per stable?

[Ref: ZNSN]

Hint: You may have to think a little laterally.

Answer:
Place one letter from TEN HORSES into each of the nine stables.

Puzzle 51

What word can prefix (go before) these letters to make a valid word in each case:

We told Cliff to run, 'Run Cliff, run'. So Cliff ran, celebrating the recent victory in the inter-departmental relay race.

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