At the recent BrainBashers downhill mountain bike race, four entrants entered the challenging slalom event.
Alan came first.
The entrant wearing number 2 wore red, whereas John didn't wear yellow.
The loser wore blue and Steve wore number 1.
Kev beat Steve and the person who came second wore number 3.
The entrant in yellow beat the entrant in green.
Only one of the entrants wore the same number as their final position.
Can you determine who finished where, the number and colour they wore?
[Ref: ZNLA] © Kevin Stone
Answer: # Name Wore Colour
1 Alan 2 red
2 Kev 3 yellow
3 Steve 1 green
4 John 4 blue
Imagine you have one cup of tea and one cup of coffee.
Place a spoonful of the tea into the coffee and stir well.
Then place a spoonful of the tea/coffee mixture back into the tea.
Does the cup of coffee now contain more tea, or the cup of tea more coffee?
Hint: The cups do not need to have the same quantity of liquid.
Surprisingly, they are actually the same.
After both swaps have taken place, both cups contain the same amount of liquid that they each started with.
So, any tea missing from the cup of tea is now in the cup of coffee.
The same amount of coffee must be now missing from the cup of coffee, and must be in the cup of tea.
This can also be shown using algebra:
If each cup contains 100 units of its respective beverage and a spoon holds 10 units, then at the start we have:
CoffeeCup = 100 Coffee
TeaCup = 100 Tea
We now transfer a spoonful of tea across to the coffee to give:
CoffeeCup = 100 Coffee + 10 Tea
TeaCup = 90 Tea
We now transfer a spoonful of the coffee/tea mixture back to the tea cup, this 10 unit spoonful will contain [10 x (100 Coffee + 10 Tea) / 110]. So we will have:
CoffeeCup = 100 Coffee + 10 Tea - [10 x (100 Coffee + 10 Tea) / 110]
TeaCup = 90 Tea + [10 x (100 Coffee + 10 Tea) / 110]
If we simplify this we get:
CoffeeCup = (10000 / 110) Coffee + (1000 / 110) Tea
TeaCup = (10000 / 110) Tea + (1000 / 110) Coffee
So there is as much coffee in the tea cup as there is tea in the coffee cup! QED.
Fred can eat 27 chocolates in a hour, Alice can eat 2 chocolates in 10 minutes, and Kelly can eat 7 chocolates in 20 minutes.
How long will it take them to share and eat a large box of 120 chocolates whilst watching a movie?
[Ref: ZGBB] © Kevin Stone
Hint: In total how many chocolates are eaten each hour.
Answer: 2 hours.
In one hour, Fred eats 27 chocolates, Alice eats 12, and Kelly eats 21. A total of 60 chocolates. Therefore 120 chocolates would take 120 ÷ 60 = 2 hours. QED.
Can you find anagrams of the following words?
[Ref: ZJYZ] © Kevin Stone
Hint: These are the first letters of the words: P, M, T, M, R, T, W, T, L, T.
Parasite, marginal, tangible, medicate, reactive, teaching, woodland, treading, latitude, teenager.
Using the BrainTracker grid below, how many words can you find? Each word must contain the central
M and no letter can be used twice, however, the letters do not have to be connected. Proper nouns are not allowed, however, plurals are. Can you find the nine letter word?
Excellent: 16 words. Good: 12 words. Average: 8 words.
[Ref: ZXXT] © Kevin Stone
Hint: Every word must contain the central letter.
em, hem, home, me, mere, mesh, mew, more, mow, mower, ohm, seem, some, SOMEWHERE, whom, worm.
em, eme, emeer, emeers, emes, ems, hem, heme, hemes, hems, herm, herms, hm, home, homer, homers, homes, me, meow, meows, mere, meres, mesh, mew, mews, mho, mhos, mo, mor, more, mores, mors, morse, mos, mow, mower, mowers, mows, ohm, ohms, om, omer, omers, oms, rehem, rehems, rem, rems, rom, roms, seem, seemer, seme, shmo, smew, some, SOMEWHERE, whom, worm, worms.