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Daily Sudoku Answer 



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May 21 - Hard
Puzzle Copyright © Kevin Stone

Share link – www.brainbashers.com/s184509



Reasoning 



R9C9 can only be <5>

R5C2 is the only square in row 5 that can be <5>

R4C7 is the only square in row 4 that can be <5>

R6C5 is the only square in row 6 that can be <3>

R8C3 is the only square in row 8 that can be <5>

R9C2 is the only square in row 9 that can be <3>

R9C5 is the only square in row 9 that can be <4>

R5C6 is the only square in column 6 that can be <6>

R2C9 is the only square in column 9 that can be <3>

Intersection of row 6 with block 4. The value <7> only appears in one or more of squares R6C1, R6C2 and R6C3 of row 6. These squares are the ones that intersect with block 4. Thus, the other (non-intersecting) squares of block 4 cannot contain this value.

R5C1 - removing <7> from <2479> leaving <249>

Intersection of row 8 with block 9. The values <68> only appears in one or more of squares R8C7, R8C8 and R8C9 of row 8. These squares are the ones that intersect with block 9. Thus, the other (non-intersecting) squares of block 9 cannot contain these values.

R7C7 - removing <8> from <128> leaving <12>

R7C8 - removing <8> from <1278> leaving <127>

Intersection of column 7 with block 3. The value <4> only appears in one or more of squares R1C7, R2C7 and R3C7 of column 7. These squares are the ones that intersect with block 3. Thus, the other (non-intersecting) squares of block 3 cannot contain this value.

R1C8 - removing <4> from <1246> leaving <126>

R3C8 - removing <4> from <1248> leaving <128>

R1C1 is the only square in row 1 that can be <4>

R5C8 is the only square in row 5 that can be <4>

R4C3 is the only square in row 4 that can be <4>

Squares R7C7<12>, R7C8<127> and R9C8<17> in block 9 form a comprehensive naked triplet. These 3 squares can only contain the 3 possibilities <127>. Since each of the squares must contain one of the possibilities, they can be eliminated from the other squares in the block.

R8C7 - removing <12> from <1268> leaving <68>

R8C9 - removing <2> from <268> leaving <68>

Intersection of row 8 with block 8. The value <2> only appears in one or more of squares R8C4, R8C5 and R8C6 of row 8. These squares are the ones that intersect with block 8. Thus, the other (non-intersecting) squares of block 8 cannot contain this value.

R7C4 - removing <2> from <2379> leaving <379>

Squares R2C1<279>, R2C5<279> and R2C6<79> in row 2 form a comprehensive naked triplet. These 3 squares can only contain the 3 possibilities <279>. Since each of the squares must contain one of the possibilities, they can be eliminated from the other squares in the row.

R2C3 - removing <79> from <6789> leaving <68>

R2C4 - removing <279> from <2479> leaving <4>

R2C7 - removing <2> from <2468> leaving <468>

R3C7 is the only square in row 3 that can be <4>

R7C7 is the only square in column 7 that can be <1>

R9C8 can only be <7>

R9C1 can only be <1>

R7C8 can only be <2>

R6C7 is the only square in column 7 that can be <2>

R5C9 can only be <8>

R8C9 can only be <6>

R8C7 can only be <8>

R1C9 can only be <2>

R2C7 can only be <6>

R2C3 can only be <8>

R1C8 can only be <1>

R1C5 can only be <9>

R3C8 can only be <8>

R3C3 can only be <7>

R3C2 can only be <2>

R7C3 can only be <9>

R6C3 can only be <6>

R8C1 can only be <7>

R7C2 can only be <8>

R1C2 can only be <6>

R4C5 can only be <8>

R5C5 can only be <7>

R2C6 can only be <7>

R2C5 can only be <2>

R7C6 can only be <3>

R3C4 can only be <3>

R2C1 can only be <9>

R3C6 can only be <1>

R7C4 can only be <7>

R8C6 can only be <9>

R5C4 can only be <9>

R6C8 can only be <9>

R4C2 can only be <9>

R6C2 can only be <7>

R4C8 can only be <6>

R8C4 can only be <2>

R5C1 can only be <2>

R8C5 can only be <1>



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