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The easiest way to solve this puzzle is to use Q1 to check the logic.

If Q1's answer was A, this tells us that Q2's answer is B, which tells us Q3's is D, which tells us Q4's answer is B, which tells us Q1's answer is C. A contradiction.

If Q1's answer was B, this tells us that Q2's answer is A, which tells us Q3's is C, which tells us Q4's answer is C, which tells us Q1's answer is A. A contradiction.

If Q1's answer was C, this tells us that Q2's answer is D, which tells us Q3's is A, which tells us Q4's answer is D, which tells us Q1's answer is B. A contradiction.

If Q1's answer was D, this tells us that Q2's answer is C, which tells us Q3's is B, which tells us Q4's answer is A, which tells us Q1's answer is D. Which is correct, and therefore the correct answer.

Puzzle 156

I have a box.

The top's area is 240 square inches, the front's area is 300 square inches and the end's area is 180 square inches.

What are the dimensions of the box?

[Ref: ZWKR]

Hint: This is a tricky puzzle and knowledge of algebra would certainly help.

Answer:
Length=20, depth=12, height=15.

This is easily solved with a little simple algebra. If we call the three sides A, B, and C we have:

A x B = 240 A x C = 300 B x C = 180

Multiplying these together we get:

(A x B) x (A x C) x (B x C) = 240 x 300 x 180

A^{2} x B^{2} x C^{2} = 12,960,000

(A x B x C)^{2} = 12,960,000

Which means that:

A x B x C = 3600

Substituting A x B = 240 back in gives C = 15 and the rest follow. QED.

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