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Below, 10 nine letter words have been broken into chunks of three letters. These chunks have been mixed up, no chunk is used twice and all chunks are used. Can you determine what the 10 words are?
rbr ent ard man tor rbo
and ban con erf dst dli
fly spa dra dif hai ght
per all fis ove ush hea
new gon fer wat her duc
Hint: Try breaking each cog size into prime factors.
Answer: 160 revolutions.
Puzzle 604
A man had to pack a sack of apples into packets but as each packet had to have exactly the same number of apples he was having difficulty.
If he packed 10 apples per packet, one packet only had 9.
If he packed 9 apples per packet, one packet only had 8.
If he packed 8 apples per packet, one packet only had 7.
If he packed 7 apples per packet, one packet only had 6.
And so on down to 2 apples.
How many apples did he start with?
[Ref: ZZQR]
Hint: The answer involves times tables.
Answer: 2519 apples.
The amount of apples divided by 10 leaves a remainder of 9, the amount of apples divided by 9 leaves a remainder of 8, etc. So we're after a number of apples that divided by 10, 9, etc leaves a remainder of one less. This can be found by using the lowest/least common multiple of 10, 9, 8, 7, 6, 5, 4, 3 and 2, and then subtracting 1.
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