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  Puzzle 1
Place the words below into pairs. You will then have 5 lots of eight letters, each of which is an anagram of another word. What are the original 5 words?
PEER
TIME
DATE
WALL
JUNE
TONE
SNOB
SEAT
PALE
VILE
 
[Ref: ZZEQ] © Kevin Stone [Protected Puzzle]
Antelope = pale + tone, juvenile = vile + june, repeated = peer + date, snowball = snob + wall, estimate = time + seat.
Puzzle 2
Hidden in the grid below are 6 hidden animals, once you have crossed of the hidden animals, you should be left with seven letters, which spell another animal. The letters are hidden in sequence using the move of a chess knight. For example, if the first letter of one of the animals was the top-right F, then the second letter could only be either F or A.
[Ref: ZDWI] © Kevin Stone [Protected Puzzle]
Hamster, the hidden animals were leopard, elephant, antelope, giraffe, kangaroo, goat:
Puzzle 3
What four related words are merged here:
SWAS PURI UINM NTTU MGER MNER
[Ref: ZAAF] © Kevin Stone [Protected Puzzle]
Spring, summer, autumn and winter.
Puzzle 4
Once upon a time, and old lady went to sell her vast quantity of eggs at the local market.
When asked how many she had, she replied:
Son, I can't count past 100 but I know that.
If you divide the number of eggs by 2 there will be one egg left.
If you divide the number of eggs by 3 there will be one egg left.
If you divide the number of eggs by 4 there will be one egg left.
If you divide the number of eggs by 5 there will be one egg left.
If you divide the number of eggs by 6 there will be one egg left.
If you divide the number of eggs by 7 there will be one egg left.
If you divide the number of eggs by 8 there will be one egg left.
If you divide the number of eggs by 9 there will be one egg left.
If you divide the number of eggs by 10 there will be one egg left.
Finally. If you divide the Number of eggs by 11 there will be NO EGGS left!
How many eggs did the old lady have?
[Ref: ZFMU] Copyrighted
25,201 eggs. This puzzle has a few different methods for finding the solution, one of which is:
Find a number X into which all of the numbers from 2 to 10 divide evenly. You can do this by simply using 2*3*4*5*6*7*8*9*10, but you can find a smaller number by finding the prime factors, a subset of which can be used to form any number from 2 to 10. 2*2*2*3*3*5*7 will do. This comes out to be 2520, and is the lowest number into which all the numbers 2-10 divide evenly.
We can add 1 to this number to satisfy the first 9 constraints of the puzzle (the remainder of 2521/2, 2521/3 ... 2521/10 is one), but this does not satisfy the last constraint, divisibility by 11.
Fortunately, we can multiply X (=2520) by any integer and add 1 and we will still satisfy constraints 1-9. So what Y do we multiply X by so that (X*Y) + 1 is divisible by 11. 2520/11 has a remainder of 1. Thus two 2520s divided by eleven would have a remainder of 1+1 = 2, and so forth...so ten 2520s divided by 11 would have a remainder of 10. This number plus one would divide eleven evenly, as well as also satisfy the first 9 constraints - thus 25201 is the answer.
Puzzle 5
In this long division, each number has been replaced by another. The answer has also been removed. Can you determine the answer?
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75 | 796767
791
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57
30
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86
82
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47
47
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9
[Ref: ZUKF] © Kevin Stone [Protected Puzzle]
6423: 109191 / 17. The numbers 1234567890 have been replaced by 7182435069 respectively.
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