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Puzzle Details

I have three children.

The youngest is the same age as the first digit in my age, another is the same age as the second digit in my age, and the third is the same age as the sum of the two digits in my age.

The total of our ages is 33.

How old am I?

The children are 2, 3 and 5.

If I was AB years of age (which is really 10 x A + B), my youngest child would be A years old, another would be B years old and the third would be A + B.

The total is therefore:

(10 x A + B) + A + B + (A + B) = 33

10A + B + A + B + A + B = 33

12A + 3B = 33

The first value for A that makes sense is A = 2, making B = 3. Although mathematically I could currently be 17, which would make my children 1, 7 and 8. This would have made me 9 years of age when I had my first child, which I wasn't!

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