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 Puzzle 393 Can you add two lines to complete this sequence of towers? [Ref: ZKNL] © Lloyd King.Lloyd has created an excellent book of lateral puzzles Hint: Look at the tops of the towers. Answer: Add the two lines to the second tower from the left to complete the 'X' in the inverted letter sequence U, V, W, X, Y forming the towers' roofs. Puzzle 394 At the local sweet shop, three particularly nice sweets are on special offer. A Sparkle, a Wibbler and a Nobbler together cost 40p. - A Nobbler is over three times the price of a Sparkle. - Six Sparkles are worth more than a Wibbler. - A Nobbler, plus two Sparkles costs less than a Wibbler. Can you determine the price of each type of sweet? [Ref: ZQVP] © Kevin Stone Hint: Which sweet is the least expensive? Answer: Sparkle =  4p Wibbler = 23p Nobbler = 13p If we label the clues. A Nobbler is over three times the price of a Sparkle.     [1] Six Sparkles are worth more than a Wibbler.               [2] A Nobbler, plus two Sparkles costs less than a Wibbler.   [3] A Sparkle, a Wibbler and a Nobbler together cost 40p.     [4] By [3] a Nobbler, plus two Sparkles costs less than a Wibbler, a Wibbler must be the most expensive sweet. By [1] a Nobbler is over three times the price of a Sparkle, a Sparkle is cheaper than a Nobbler and hence the cheapest sweet. So the order of sweets, from the least to most expensive, is Sparkle, Nobbler, Wibbler. If a Sparkle was 1p, by [2] a Wibbler could only be up to 5p, by [4] a Nobbler would cost at least 34p, which is more than a Wibbler and isn't allowed as the Wibbler is the most expensive sweet. If a Sparkle was 2p, by [2] a Wibbler could only be up to 11p, by [4] a Nobbler would cost at least 27p, which is more than a Wibbler and isn't allowed as the Wibbler is the most expensive sweet. If a Sparkle was 3p, by [2] a Wibbler could only be up to 17p, by [4] a Nobbler would cost at least 20p, which is more than a Wibbler and isn't allowed as the Wibbler is the most expensive sweet. So a Sparkle must be at least 4p. If a Sparkle was 4p, by [1] a Nobbler must be at least 13p, by [4] a Wibbler would cost 23p - this combination matches all of the clues and is a possible solution. If a Sparkle was 4p and a Nobbler 14p, by [4] a Wibbler would cost 22p. This would not satisfy [3]. And if we increase the price of a Nobbler, [3] is never satisfied. If a Sparkle was 5p, by [1] a Nobbler must be at least 16p, by [4] making a Wibbler at most 19p. This would not satisfy [3]. If we increase the price of a Sparkle or Nobbler further, [3] is will never be satisfied. Therefore the only solution we came across must be the correct one. QED. Puzzle 395 What is represented by this BrainBat? CITY [Ref: ZWQE] Hint: Say what you see. Answer: Capital city. Puzzle 396 Can you find three consecutive even numbers that total 85,008 when multiplied together? [Ref: ZEZT] © Kevin Stone Hint: Try starting with the cube root of the number. Answer: 42, 44 and 46.