Below you will find ten 6 letter words, however, every other letter is missing.
Can you determine the words?
[Ref: ZAGD] © Kevin Stone
Hint: The first word begins with the letter A.
_S_E_D = ASCEND
_P_A_G = SPRANG
_R_F_R = PREFER
_Y_R_D = HYBRID
_R_F_E = TRIFLE
_A_B_N = CARBON
_A_E_A = CAMERA
_O_D_G = HOTDOG
_S_F_L = USEFUL
_I_S_E = TISSUE
My local bus company has recently expanded and no longer has enough room for all of its buses.
Twelve of their buses have to be stored outside.
If they decide to increase their garage space by 40%, this will give them enough room for all of their current buses, plus enough room to store another twelve in the future.
How many buses does the company currently own?
[Ref: ZWOL] © Kevin Stone
Hint: A tricky puzzle that will need a little algebra (or clever thinking).
They have enough room for 60 of these, expanding the 60 capacity by 40% will give them enough room for 84, which we know is 12 more spaces than they currently need.
If they have B buses and S spaces before the expansion, they have enough room for:
S = B - 12 
After the expansion they have more spaces, and enough room for:
S + 0.4 x S = B + 12 
Rewriting  as:
1.4S = B + 12
and again as
B = 1.4S - 12 
We can rewrite  as:
B = S + 12 
Making  =  we have:
1.4S - 12 = S + 12
Subtracting S from both sides gives:
0.4S - 12 = 12
Adding 12 to both sides gives:
0.4S = 24
Multiplying by 10 and dividing by 4 on both sides gives:
S = 60
Using S = 60 in  gives B = 72. QED.
As my birthday approaches I start to collect leaves - a little bizarre perhaps, but I enjoy it!
On the first day of the month I collect 1 leaf, on the second day I collect 2 leaves, the third day I collect 3 leaves, and so on.
By my birthday I will have collected 276 leaves altogether. On which day of the month is my birthday?
[Ref: ZQUZ] © Kevin Stone
Hint: How many will I have collected by day 5?
Answer: On the 23rd.
276 = 1 + 2 + 3 + 4 + 5 + 6 + 7 + 8 + 9 + 10 + 11 + 12 + 13 + 14 + 15 + 16 + 17 + 18 + 19 + 20 + 21 + 22 + 23.
I have a box.
The top's area is 240 square inches, the front's area is 300 square inches and the end's area is 180 square inches.
What are the dimensions of the box?
Hint: This is a tricky puzzle and knowledge of algebra would certainly help.
Length=20, depth=12, height=15.
This is easily solved with a little simple algebra. If we call the three sides A, B, and C we have:
A x B = 240
A x C = 300
B x C = 180
Multiplying these together we get:
(A x B) x (A x C) x (B x C) = 240 x 300 x 180
A2 x B2 x C2 = 12,960,000
(A x B x C)2 = 12,960,000
Which means that:
A x B x C = 3600
Substituting A x B = 240 back in gives C = 15 and the rest follow. QED.