By changing the third letter of each of the words below, can you make another valid word.
You have to change each word such that the third letters will reveal a ten letter word when read downwards.
Therefore, what now reads KRZSAPROKD will be a real word.
[Ref: ZHEF] © Kevin Stone
Hint: The first word is BASE.
At the recent BrainBashers Festival, the 100 metres heats were closely monitored.
Each contestant had to run in two races so that the average place could be determined.
Only one runner finished in the same place in both races.
Alan was never last. Charlie always beat Darren. Brian had at least one first place. Alan finished third in at least one of the races. Both Darren and Charlie had a second place.
What were the two results?
[Ref: ZMKA] © Kevin Stone
Hint: Since Darren had a second place, what does this tell us about Charlie?
Race 1: Brian, Charlie, Alan, Darren.
Race 2: Charlie, Darren, Alan, Brian.
To explain - since Charlie always beat Darren and Darren had a second place, one race must have been Charlie first and Darren second. Brian therefore won the other race with Charlie second. Since only one runner finished in the same place in both races, this must have been Alan in third. QED.
Practical Peter was asked to cut a 99 foot rope into three smaller, equal length ropes.
However, as usual, Pete couldn't find his measuring tape so he guessed!
When he finally did find his tape (it was under his hat), he discovered that:
A) the second piece of rope was twice as long as the first piece, minus 35 feet (i.e. 2 x first, - 35).
B) the third piece of rope was half the length of the first, plus 15 feet (i.e. 0.5 x first, + 15)
How long were each of the pieces of rope?
[Ref: ZGCD] © Kevin Stone
Hint: Only one of the ropes was 33 feet.
First = 34 feet.
Second = 33 feet.
Third = 32 feet.
This question can be solved easily using algebra, if we call the length of the first rope A, we have:
Rope 1 = A
Rope 2 = 2 x A - 35
Rope 3 = 1 ÷ 2 x A + 15
The three ropes add to 99 feet, so:
99 = Rope 1 + Rope 2 + Rope 3
99 = A + (2 x A - 35) + 1 ÷ 2 x A + 15
99 = 3.5 x A - 20
Adding 20 to both sides we have:
119 = 3.5 x A
A = 119 ÷ 3.5
A = Rope 1 = 34 feet
Rope 2 = 2 x 34 - 35 = 68 - 35 = 33 feet
Rope 3 = 1 ÷ 2 x A + 15 = 1 ÷ 2 x 34 + 15 = 17 + 15 = 32 feet
Just to check:
Rope 1 + Rope 2 + Rope 3 = 34 + 33 + 32 = 99.
As required. QED.
Below you will find 15 well-known six letter words, with only their endings remaining. Can you determine the words?
[Ref: ZNFZ] © Kevin Stone
Hint: The first 6 words begin with the letters D, A, Q, S, W, S.
...amt >> dreamt
...nue >> avenue
...rtz >> quartz
...oze >> snooze
...mth >> warmth
...iek >> shriek
...gry >> hungry
...thm >> rhythm
...koo >> cuckoo
...spy >> crispy
...sip >> gossip
...lem >> emblem
...uid >> liquid
...tyr >> martyr
...meg >> nutmeg
Can you find the anagrams of the following words?
[Ref: ZKRV] © Kevin Stone
Hint: Each word only has one anagram.